feat(Go-Tool):新增二分法查找算法及其单测、插入查询及其单测、lomuto划分查询第k小元素及其单测、归并排序及其单测、快速排序及其单测.

This commit is contained in:
huangzj
2020-08-20 09:28:35 +08:00
parent fa58e1a97f
commit c2aca17567
12 changed files with 385 additions and 8 deletions
+28
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@@ -0,0 +1,28 @@
/*
* @Author : huangzj
* @Time : 2020/8/18 17:45
* @Description:二分查找法,对于有序数组进行查找
*/
package search
func BinarySearch(list []int, value int) int {
low := 0
high := len(list) - 1
var mid int
for low <= high {
mid = (low + high) >> 1 //相当于(low + high) / 2
if value == list[mid] {
return mid
}
if value < list[mid] {
high = mid - 1
} else {
low = mid + 1
}
}
return -1
}
+42
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/*
* @Author : huangzj
* @Time : 2020/8/18 17:59
* @Description
*/
package search
import (
"fmt"
"testing"
)
func TestBinarySearch(t *testing.T) {
evenNumList := []int{1, 2, 3, 5, 6, 7, 9, 10, 22, 111, 333, 431}
for _, r := range evenNumList {
position := BinarySearch(evenNumList, r)
fmt.Println(position)
}
position := BinarySearch(evenNumList, 999)
fmt.Println(position)
position = BinarySearch(evenNumList, -10)
fmt.Println(position)
fmt.Println()
oddNumList := []int{1, 2, 3, 5, 6, 7, 9, 10, 22, 111, 333, 431, 3211}
for _, r := range oddNumList {
position := BinarySearch(oddNumList, r)
fmt.Println(position)
}
position = BinarySearch(oddNumList, 999)
fmt.Println(position)
position = BinarySearch(oddNumList, -10)
fmt.Println(position)
}
+34
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/*
* @Author : huangzj
* @Time : 2020/8/19 10:24
* @Description
*
*/
package search
func InsertionSearch(list []int, value int) int {
low := 0
high := len(list) - 1
var mid int
//插值查找这边如果数字和起始数字差别大的话,计算出来的下标会越界挺多的
if value > list[high-1] || value < list[0] {
return -1
}
for low < high {
mid = low + (high-low)*(value-list[low])/(list[high]-list[low])
if value == list[mid] {
return mid
}
if value < list[mid] {
high = mid - 1
} else {
low = mid + 1
}
}
return -1
}
+7
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从折半查找中可以看出,折半查找的查找效率还是不错的。可是为什么要折半呢?为什么不是四分之一、八分之一呢?打个比方,在牛津词典里要查找“apple”这个单词,会首先翻开字典的中间部分,然后继续折半吗?
肯定不会,对于查找单词“apple”,我们肯定是下意识的往字典的最前部分翻去,而查找单词“zero”则相反,我们会下意识的往字典的最后部分翻去。
所以在折半查找法的基础上进行改造就出现了插值查找法,也叫做按比例查找。所以插值查找与折半查找唯一不同的是在于mid的计算方式上,它的计算方式为:
mid = low + (high - low) * (searchValue - data[low]) / (data[high] - data[low])
插值查找的时间复杂度也是O(log2n),但是对于数据集合较长,且关键字分布比较均匀的数据集合来说,插值查找的算法性能比折半查找要好,其它的则不适用。
+42
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/*
* @Author : huangzj
* @Time : 2020/8/19 10:38
* @Description
*/
package search
import (
"fmt"
"testing"
)
func TestInsertionSearch(t *testing.T) {
evenNumList := []int{1, 2, 3, 5, 6, 7, 9, 10, 22, 111, 333, 431}
for _, r := range evenNumList {
position := InsertionSearch(evenNumList, r)
fmt.Println(position)
}
position := InsertionSearch(evenNumList, 999)
fmt.Println(position)
position = InsertionSearch(evenNumList, -10)
fmt.Println(position)
fmt.Println()
oddNumList := []int{1, 2, 3, 5, 6, 7, 9, 10, 22, 111, 333, 431, 3211}
for _, r := range oddNumList {
position := InsertionSearch(oddNumList, r)
fmt.Println(position)
}
position = InsertionSearch(oddNumList, 999)
fmt.Println(position)
position = InsertionSearch(oddNumList, -10)
fmt.Println(position)
}
+4 -4
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@@ -11,7 +11,7 @@ package search
//start : 开始比较的数字下标
//end :结束比较的数字下标
//作用说明:
func partition(list []int, start int, end int) int {
func LomutoPartition(list []int, start int, end int) int {
moveSubscript := start
compareValue := list[start]
for i := start + 1; i <= end; i++ {
@@ -27,13 +27,13 @@ func partition(list []int, start int, end int) int {
func LomutoQuiteSelect(list []int, pointPosition int) int {
positionCheck(pointPosition, len(list)) //下标校验
nowPosition := partition(list, 0, len(list)-1)
nowPosition := LomutoPartition(list, 0, len(list)-1)
//循环进行lomuto划分处理,知道找到我们需要的那个位置的元素
for nowPosition != pointPosition-1 {
if nowPosition > pointPosition-1 {
nowPosition = partition(list, 0, nowPosition)
nowPosition = LomutoPartition(list, 0, nowPosition)
} else {
nowPosition = partition(list, nowPosition+1, len(list)-1)
nowPosition = LomutoPartition(list, nowPosition+1, len(list)-1)
}
}
+2 -2
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@@ -13,13 +13,13 @@ import (
func TestPartition(t *testing.T) {
list := []int{99, 1, 2, 3, 4, 100, 200, 90, 5}
s := partition(list, 0, 9-1)
s := LomutoPartition(list, 0, 9-1)
fmt.Println(fmt.Sprintf("当前第一个元素应该存在位置为:%d", s))
for _, r := range list {
fmt.Print(r, " ")
}
s = partition(list, 0, 9-1)
s = LomutoPartition(list, 0, 9-1)
fmt.Println(fmt.Sprintf("当前第一个元素应该存在位置为:%d", s))
for _, r := range list {
fmt.Print(r, " ")
+54
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/*
* @Author : huangzj
* @Time : 2020/8/19 11:44
* @Description:这边提供一个递归的归并排序算法,非递归的理解成本比较高,并且还有多路归并排序,需要理解对应概念
* 最坏时间复杂度O(nlogn) 最好时间复杂度O(logn) 空间复杂度O(n)
*/
package sort
func MergeSort(list []int) {
middle := len(list) / 2
leftList := copyList(list, 0, middle)
rightList := copyList(list, middle, len(list))
if len(list) > 1 {
MergeSort(leftList) //先对左边进行归并排序
MergeSort(rightList) //再对右边进行归并排序
mergeAll(list, leftList, rightList) //对左右排序的结果进行组合
}
}
func copyList(list []int, start int, end int) []int {
result := make([]int, 0)
for i := start; i < end; i++ {
result = append(result, list[i])
}
return result
}
func mergeAll(array []int, left []int, right []int) {
l, r, i := 0, 0, 0 //左数组的下标、右数组的下标、组合数组的下标
for l < len(left) && r < len(right) {
if left[l] > right[r] {
array[i] = right[r]
i++
r++
} else {
array[i] = left[l]
i++
l++
}
}
for r < len(right) {
array[i] = right[r]
r++
i++
}
for l < len(left) {
array[i] = left[l]
l++
i++
}
}
+42
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/*
* @Author : huangzj
* @Time : 2020/8/19 11:45
* @Description
*/
package sort
import (
"fmt"
"testing"
)
func TestMergeSort(t *testing.T) {
list1 := []int{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
MergeSort(list1)
for _, r := range list1 {
fmt.Print(r, " ")
}
fmt.Println()
list2 := []int{10, 9, 8, 7, 6, 5, 4, 3, 2, 1}
MergeSort(list2)
for _, r := range list2 {
fmt.Print(r, " ")
}
fmt.Println()
list3 := []int{100, 5, 222, 312, 552, 354, 8, 21, 90, 2, 0, 12, 345, 67}
MergeSort(list3)
for _, r := range list3 {
fmt.Print(r, " ")
}
fmt.Println()
list4 := []int{1, 19, 42, 7, 3131, 44, 56, 123, 589, 21, 975, 123, 5467, 143, 7, 321, 77, 3}
MergeSort(list4)
for _, r := range list4 {
fmt.Print(r, " ")
}
fmt.Println()
}
+46
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/*
* @Author : huangzj
* @Time : 2020/8/19 17:06
* @Description
*/
package sort
import "Go-Tool/util/search"
//通过hoare划分来实现快速排序
func QuickSort(list []int, start, end int) {
if start < end {
position := hoarePartition(list, start, end)
QuickSort(list, start, position) //注意这边结束的下表是position,而不是position + 1
QuickSort(list, position+1, end)
}
}
//通过lomuto划分来实现快速排序
func QuickSort1(list []int, start, end int) {
if start < end {
position := search.LomutoPartition(list, start, end)
QuickSort(list, start, position)
QuickSort(list, position+1, end)
}
}
func hoarePartition(list []int, start int, end int) int {
value := list[start] //比较的元素
s := start
e := end
for s < e {
//找到数组终止前,比目标数(value)大的数字
for ; s < end && list[s] < value; s++ {
}
//找到数组结束前,比目标数(value)小的数字
for ; e > start && list[e] >= value; e-- {
}
if s < e {
list[s], list[e] = list[e], list[s]
}
}
list[start], list[e] = list[e], list[start]
return e
}
+80
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/*
* @Author : huangzj
* @Time : 2020/8/19 17:57
* @Description
*/
package sort
import (
"fmt"
"testing"
)
func TestQuickSort(t *testing.T) {
list := []int{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
QuickSort(list, 0, len(list)-1)
for _, r := range list {
fmt.Print(r, " ")
}
fmt.Println()
list1 := []int{10, 9, 8, 7, 6, 5, 4, 3, 2, 1}
QuickSort(list1, 0, len(list1)-1)
for _, r := range list1 {
fmt.Print(r, " ")
}
fmt.Println()
list2 := []int{432, 412, 213, 456, 7, 213, 4, 78, 13, 87, 312321, 456, 7, 231, 234, 3}
QuickSort(list2, 0, len(list2)-1)
for _, r := range list2 {
fmt.Print(r, " ")
}
fmt.Println()
list3 := []int{1, 312, 356, 76, 2, 54, 78, 321, 3455, 65732, 123534, 54351, 4213, 123, 56, 6, 732, 123, 44, 51, 5, 61, 543}
QuickSort(list3, 0, len(list3)-1)
for _, r := range list3 {
fmt.Print(r, " ")
}
fmt.Println()
}
func TestQuickSort1(t *testing.T) {
list := []int{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
QuickSort1(list, 0, len(list)-1)
for _, r := range list {
fmt.Print(r, " ")
}
fmt.Println()
list1 := []int{10, 9, 8, 7, 6, 5, 4, 3, 2, 1}
QuickSort1(list1, 0, len(list1)-1)
for _, r := range list1 {
fmt.Print(r, " ")
}
fmt.Println()
list2 := []int{432, 412, 213, 456, 7, 213, 4, 78, 13, 87, 312321, 456, 7, 231, 234, 3}
QuickSort1(list2, 0, len(list2)-1)
for _, r := range list2 {
fmt.Print(r, " ")
}
fmt.Println()
list3 := []int{1, 312, 356, 76, 2, 54, 78, 321, 3455, 65732, 123534, 54351, 4213, 123, 56, 6, 732, 123, 44, 51, 5, 61, 543}
QuickSort1(list3, 0, len(list3)-1)
for _, r := range list3 {
fmt.Print(r, " ")
}
fmt.Println()
}