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Go-tool/util/search/LomutoPartition.go
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/*
* @Author : huangzj
* @Time : 2020/8/18 14:11
* @DescriptionLomuto划分,找到一个数组中第k个小的元素.这边只是提供一个示例,具体类型可以根据该算法进行修改
*/
package search
var (
times = 0 //用来计算一次划分进行了多少次的比较操作
charge = 0 //实际进行元素交换的次数
)
//参数说明:
//list :数组
//start : 开始比较的数字下标
//end :结束比较的数字下标
//作用说明:
func LomutoPartition(list []int, start int, end int) int {
moveSubscript := start
compareValue := list[start]
for i := start + 1; i <= end; i++ {
if list[i] < compareValue {
moveSubscript++
charge++
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list[moveSubscript], list[i] = list[i], list[moveSubscript] //交换元素
}
}
charge++
list[moveSubscript], list[start] = list[start], list[moveSubscript] //交换元素
return moveSubscript
}
func LomutoQuiteSelect(list []int, pointPosition int) (int, int, int) {
positionCheck(pointPosition, len(list)) //下标校验
times = 0
charge = 0
nowPosition := LomutoPartition(list, 0, len(list)-1)
times++
//循环进行lomuto划分处理,知道找到我们需要的那个位置的元素
for nowPosition != pointPosition-1 {
times++
if nowPosition > pointPosition-1 {
nowPosition = LomutoPartition(list, 0, nowPosition)
} else {
nowPosition = LomutoPartition(list, nowPosition+1, len(list)-1)
}
}
return list[nowPosition], times, charge
}
func positionCheck(pointPosition int, len int) {
if pointPosition <= 0 || pointPosition > len {
panic("查询的元素下标不能小于0,或者大于数组长度")
}
}