feat(Go-Tool):新增二分法查找算法及其单测、插入查询及其单测、lomuto划分查询第k小元素及其单测、归并排序及其单测、快速排序及其单测.
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@@ -0,0 +1,28 @@
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/*
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* @Author : huangzj
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* @Time : 2020/8/18 17:45
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* @Description:二分查找法,对于有序数组进行查找
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*/
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package search
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func BinarySearch(list []int, value int) int {
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low := 0
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high := len(list) - 1
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var mid int
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for low <= high {
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mid = (low + high) >> 1 //相当于(low + high) / 2
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if value == list[mid] {
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return mid
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}
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if value < list[mid] {
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high = mid - 1
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} else {
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low = mid + 1
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}
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}
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return -1
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}
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@@ -0,0 +1,42 @@
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/*
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* @Author : huangzj
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* @Time : 2020/8/18 17:59
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* @Description:
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*/
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package search
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import (
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"fmt"
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"testing"
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)
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func TestBinarySearch(t *testing.T) {
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evenNumList := []int{1, 2, 3, 5, 6, 7, 9, 10, 22, 111, 333, 431}
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for _, r := range evenNumList {
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position := BinarySearch(evenNumList, r)
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fmt.Println(position)
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}
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position := BinarySearch(evenNumList, 999)
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fmt.Println(position)
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position = BinarySearch(evenNumList, -10)
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fmt.Println(position)
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fmt.Println()
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oddNumList := []int{1, 2, 3, 5, 6, 7, 9, 10, 22, 111, 333, 431, 3211}
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for _, r := range oddNumList {
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position := BinarySearch(oddNumList, r)
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fmt.Println(position)
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}
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position = BinarySearch(oddNumList, 999)
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fmt.Println(position)
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position = BinarySearch(oddNumList, -10)
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fmt.Println(position)
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}
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@@ -0,0 +1,34 @@
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/*
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* @Author : huangzj
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* @Time : 2020/8/19 10:24
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* @Description:
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*
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*/
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package search
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func InsertionSearch(list []int, value int) int {
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low := 0
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high := len(list) - 1
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var mid int
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//插值查找这边如果数字和起始数字差别大的话,计算出来的下标会越界挺多的
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if value > list[high-1] || value < list[0] {
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return -1
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}
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for low < high {
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mid = low + (high-low)*(value-list[low])/(list[high]-list[low])
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if value == list[mid] {
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return mid
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}
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if value < list[mid] {
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high = mid - 1
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} else {
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low = mid + 1
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}
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}
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return -1
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}
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@@ -0,0 +1,7 @@
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从折半查找中可以看出,折半查找的查找效率还是不错的。可是为什么要折半呢?为什么不是四分之一、八分之一呢?打个比方,在牛津词典里要查找“apple”这个单词,会首先翻开字典的中间部分,然后继续折半吗?
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肯定不会,对于查找单词“apple”,我们肯定是下意识的往字典的最前部分翻去,而查找单词“zero”则相反,我们会下意识的往字典的最后部分翻去。
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所以在折半查找法的基础上进行改造就出现了插值查找法,也叫做按比例查找。所以插值查找与折半查找唯一不同的是在于mid的计算方式上,它的计算方式为:
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mid = low + (high - low) * (searchValue - data[low]) / (data[high] - data[low])
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插值查找的时间复杂度也是O(log2n),但是对于数据集合较长,且关键字分布比较均匀的数据集合来说,插值查找的算法性能比折半查找要好,其它的则不适用。
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@@ -0,0 +1,42 @@
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/*
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* @Author : huangzj
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* @Time : 2020/8/19 10:38
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* @Description:
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*/
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package search
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import (
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"fmt"
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"testing"
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)
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func TestInsertionSearch(t *testing.T) {
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evenNumList := []int{1, 2, 3, 5, 6, 7, 9, 10, 22, 111, 333, 431}
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for _, r := range evenNumList {
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position := InsertionSearch(evenNumList, r)
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fmt.Println(position)
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}
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position := InsertionSearch(evenNumList, 999)
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fmt.Println(position)
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position = InsertionSearch(evenNumList, -10)
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fmt.Println(position)
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fmt.Println()
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oddNumList := []int{1, 2, 3, 5, 6, 7, 9, 10, 22, 111, 333, 431, 3211}
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for _, r := range oddNumList {
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position := InsertionSearch(oddNumList, r)
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fmt.Println(position)
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}
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position = InsertionSearch(oddNumList, 999)
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fmt.Println(position)
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position = InsertionSearch(oddNumList, -10)
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fmt.Println(position)
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}
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@@ -11,7 +11,7 @@ package search
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//start : 开始比较的数字下标
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//end :结束比较的数字下标
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//作用说明:
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func partition(list []int, start int, end int) int {
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func LomutoPartition(list []int, start int, end int) int {
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moveSubscript := start
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compareValue := list[start]
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for i := start + 1; i <= end; i++ {
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@@ -27,13 +27,13 @@ func partition(list []int, start int, end int) int {
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func LomutoQuiteSelect(list []int, pointPosition int) int {
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positionCheck(pointPosition, len(list)) //下标校验
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nowPosition := partition(list, 0, len(list)-1)
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nowPosition := LomutoPartition(list, 0, len(list)-1)
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//循环进行lomuto划分处理,知道找到我们需要的那个位置的元素
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for nowPosition != pointPosition-1 {
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if nowPosition > pointPosition-1 {
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nowPosition = partition(list, 0, nowPosition)
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nowPosition = LomutoPartition(list, 0, nowPosition)
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} else {
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nowPosition = partition(list, nowPosition+1, len(list)-1)
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nowPosition = LomutoPartition(list, nowPosition+1, len(list)-1)
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}
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}
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@@ -13,13 +13,13 @@ import (
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func TestPartition(t *testing.T) {
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list := []int{99, 1, 2, 3, 4, 100, 200, 90, 5}
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s := partition(list, 0, 9-1)
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s := LomutoPartition(list, 0, 9-1)
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fmt.Println(fmt.Sprintf("当前第一个元素应该存在位置为:%d", s))
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for _, r := range list {
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fmt.Print(r, " ")
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}
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s = partition(list, 0, 9-1)
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s = LomutoPartition(list, 0, 9-1)
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fmt.Println(fmt.Sprintf("当前第一个元素应该存在位置为:%d", s))
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for _, r := range list {
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fmt.Print(r, " ")
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