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Go-StudyExample/leetCode/simple/MajorityElement/MajorityElement1_test.go
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/*
* @Author : huangzj
* @Time : 2020/12/24 15:18
* @Description
*/
package simple
import (
"fmt"
"testing"
)
type MajorityElement1 struct{}
func (MajorityElement1) Description(string) string {
return `
给定一个大小为 n 的数组,找到其中的多数元素。多数元素是指在数组中出现次数大于 ⌊ n/2 ⌋ 的元素。
你可以假设数组是非空的,并且给定的数组总是存在多数元素。
示例 1:
输入: [3,2,3]
输出: 3
示例 2:
输入: [2,2,1,1,1,2,2]
输出: 2
`
}
//思路说明:
func majorityElement1(nums []int) int {
var result, count int
for _, num := range nums {
if count == 0 {
result = num
count++
continue
}
if num == result {
count++
continue
}
count--
}
return result
}
func TestMajorityElement1(t *testing.T) {
fmt.Println(majorityElement1([]int{3, 2, 3}))
fmt.Println(majorityElement1([]int{2, 2, 1, 1, 1, 2, 2}))
fmt.Println(majorityElement1([]int{3, 3, 4}))
}