75 lines
1.5 KiB
Go
75 lines
1.5 KiB
Go
/*
|
||
* @Author : huangzj
|
||
* @Time : 2020/12/21 23:01
|
||
* @Description:
|
||
*/
|
||
|
||
package simple
|
||
|
||
import (
|
||
"fmt"
|
||
"testing"
|
||
)
|
||
|
||
type LongestCommonPrefix struct{}
|
||
|
||
func (LongestCommonPrefix) Description(string) string {
|
||
return `
|
||
编写一个函数来查找字符串数组中的最长公共前缀。
|
||
|
||
如果不存在公共前缀,返回空字符串 ""。
|
||
|
||
示例 1:
|
||
|
||
输入: ["flower","flow","flight"]
|
||
输出: "fl"
|
||
示例 2:
|
||
|
||
输入: ["dog","racecar","car"]
|
||
输出: ""
|
||
解释: 输入不存在公共前缀。
|
||
`
|
||
}
|
||
|
||
//思路分析:最长前缀其实就是求最长字符串长度.所以第一个字符串作为公共字符串,然后循环所有的字符串,进行公共字符串的缩减
|
||
func longestCommonPrefix(strs []string) string {
|
||
if len(strs) == 0 {
|
||
return ""
|
||
}
|
||
|
||
var match []byte
|
||
for index, str := range strs {
|
||
if index == 0 {
|
||
match = []byte(str)
|
||
continue
|
||
}
|
||
position := getPosition(match, str)
|
||
match = match[0:position]
|
||
}
|
||
|
||
return string(match)
|
||
}
|
||
|
||
func getPosition(match []byte, str string) int {
|
||
var position int
|
||
for i, m := range []byte(str) {
|
||
if len(match)-1 < i {
|
||
break
|
||
}
|
||
if m == match[i] {
|
||
position++
|
||
continue
|
||
}
|
||
break
|
||
}
|
||
|
||
return position
|
||
}
|
||
|
||
func TestLongestCommonPrefix(t *testing.T) {
|
||
fmt.Println(longestCommonPrefix([]string{"flower", "flow", "flight"}))
|
||
fmt.Println(longestCommonPrefix([]string{"flow", "flower", "flight"}))
|
||
fmt.Println(longestCommonPrefix([]string{"dog", "racecar", "car"}))
|
||
fmt.Println(longestCommonPrefix([]string{"cir", "car"}))
|
||
}
|