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Go-StudyExample/SourceAnalysisAndTool/jdkContainer/sourceAnalysis/ring.go
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2020-12-31 16:48:30 +08:00
// Copyright 2009 The Go Authors. All rights reserved.
// Use of this source code is governed by a BSD-style
// license that can be found in the LICENSE file.
// Package ring implements operations on circular lists.
package sourceAnalysis
// A Ring is an element of a circular list, or ring.
// Rings do not have a beginning or end; a pointer to any ring element
// serves as reference to the entire ring. Empty rings are represented
// as nil Ring pointers. The zero value for a Ring is a one-element
// ring with a nil Value.
//
//read note 环结构:指针可能指向任意元素,空链表只有一个nil元素
type Ring struct {
next, prev *Ring
Value interface{} // for use by client; untouched by this library
}
//read note 初始化只是做了指针指向,不会增加环的值
func (r *Ring) init() *Ring {
r.next = r
r.prev = r
return r
}
// Next returns the next ring element. r must not be empty.
//read note:环的下一个值,如果环的next为空,则初始化该环
func (r *Ring) Next() *Ring {
if r.next == nil {
return r.init()
}
return r.next
}
// Prev returns the previous ring element. r must not be empty.
func (r *Ring) Prev() *Ring {
if r.next == nil {
return r.init()
}
return r.prev
}
// Move moves n % r.Len() elements backward (n < 0) or forward (n >= 0)
// in the ring and returns that ring element. r must not be empty.
//
//read note 对环上的当前元素进行n次位置的移动,小于0则向后移动,大于0则向前移动
func (r *Ring) Move(n int) *Ring {
if r.next == nil {
return r.init()
}
switch {
case n < 0:
for ; n < 0; n++ {
r = r.prev
}
case n > 0:
for ; n > 0; n-- {
r = r.next
}
}
return r
}
// New creates a ring of n elements.
//read note 创建n个节点的环
func New1(n int) *Ring {
if n <= 0 {
return nil
}
r := new(Ring)
p := r
for i := 1; i < n; i++ {
p.next = &Ring{prev: p}
p = p.next
}
p.next = r
r.prev = p
return r
}
// Link connects ring r with ring s such that r.Next()
// becomes s and returns the original value for r.Next().
// r must not be empty.
//
// If r and s point to the same ring, linking
// them removes the elements between r and s from the ring.
// The removed elements form a subring and the result is a
// reference to that subring (if no elements were removed,
// the result is still the original value for r.Next(),
// and not nil).
//
// If r and s point to different rings, linking
// them creates a single ring with the elements of s inserted
// after r. The result points to the element following the
// last element of s after insertion.
//
//read note 链接环,如果是两个相同的环则环不改变,链接完环会少掉原来的第一个元素....(神奇)
// 如果是两个不同的环,则把另一个环接到上一个环的后面,链接完的第一个元素是原来环的next的元素.第二个元素
func (r *Ring) Link(s *Ring) *Ring {
n := r.Next()
if s != nil {
p := s.Prev()
// Note: Cannot use multiple assignment because
// evaluation order of LHS is not specified.
r.next = s
s.prev = r
n.prev = p
p.next = n
}
return n
}
// Unlink removes n % r.Len() elements from the ring r, starting
// at r.Next(). If n % r.Len() == 0, r remains unchanged.
// The result is the removed subring. r must not be empty.
//
//read note 断开环上n个元素,这里会根据n%r.Len 得到的余数进行Unlink,因为环是没有起点终点的,所以超过或者不超过环的长度都是按照余数进行处理
func (r *Ring) Unlink(n int) *Ring {
if n <= 0 {
return nil
}
return r.Link(r.Move(n + 1))
}
// Len computes the number of elements in ring r.
// It executes in time proportional to the number of elements.
//
func (r *Ring) Len() int {
n := 0
if r != nil {
n = 1
for p := r.Next(); p != r; p = p.next {
n++
}
}
return n
}
// Do calls function f on each element of the ring, in forward order.
// The behavior of Do is undefined if f changes *r.
//read note 对环上的所有元素进行函数操作,但是这边的操作好像是没办法改变环中的元素的,只能进行提取或者输出
func (r *Ring) Do(f func(interface{})) {
if r != nil {
f(r.Value)
for p := r.Next(); p != r; p = p.next {
f(p.Value)
}
}
}